If $ \frac{3x+1}{(x-1)(x+3)} = \frac{A}{x-1} + \frac{B}{x+3} $, then $ \sin^{-1} \frac{A}{B} = $

Question

$ \frac{\pi}{2} $

$ \pi $

$ \frac{\pi}{6} $

$ \frac{\pi}{4} $

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