The equations of the two tangents from $(-5, -4)$ to the circle $x^2 + y^2 + 4x + 6y + 8 = 0$ are:

Question

$x + 2y + 13 = 0$, $2x - y + 6 = 0$

$2x + y + 13 = 0$, $x - 2y = 6$

$3x + 2y + 23 = 0$, $2x - 3y + 4 = 0$

$x - 7y = 23$, $6x + 13y = 4$

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