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Question

If $n \in \mathbb{N}$ and $I_n = \int (\log x)^n \, dx$, then $I_n + nI_{n-1} =$

$\frac{(\log x)^{n+1}}{n+1}$

$x(\log x)^n + c$

$\frac{(\log x)^{n-1}}{n}$

$\frac{(\log x)^n}{x}$

Solution

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