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Question

In triangle ABC, if $ \frac{\cos A}{a} = \frac{\cos B}{b} = \frac{\cos C}{c} $ and $ a = 2 $, then its area is ______

$2\sqrt{3}$

$\sqrt{3}$

$\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{4}$

Solution

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