If $ \vec{a} \perp \vec{b} $ and $ (\vec{a} + \vec{b}) \perp (\vec{a} + m\vec{b}) $, then $ m = \, \underline{\phantom{m}} $

Question

-1

$-\frac{|\vec{a}|^2}{|\vec{b}|^2}$

Please login to view the detailed solution steps...