Question
The sum of the squares of the eccentricities of the conics $\frac{x^2}{4} + \frac{y^2}{3} = 1$ and $\frac{x^2}{4} - \frac{y^2}{3} = 1$ is
The sum of the squares of the eccentricities of the conics $\frac{x^2}{4} + \frac{y^2}{3} = 1$ and $\frac{x^2}{4} - \frac{y^2}{3} = 1$ is