If $x + y = \tan^{-1} y$ and $\frac{d^2 y}{dx^2} = f(y) \frac{dy}{dx}$, then $f(y) = $ - DASH

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Question

If $x + y = \tan^{-1} y$ and $\frac{d^2 y}{dx^2} = f(y) \frac{dy}{dx}$, then $f(y) = $

$-\frac{2}{y^3}$

$\frac{2}{y^3}$

$\frac{1}{y}$

$-\frac{1}{y}$

Solution

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