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Question

Lines $(\frac{x-2}{1} = \frac{y-3}{1} = \frac{z-4}{-k})$ and $(\frac{x-1}{k} = \frac{y-4}{2} = \frac{z-5}{1})$ are coplanar if

$(k=0)$

$(k=-1)$

$(k=2)$

$(k=3)$

Solution

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