If the 21st and 22nd terms in the expansion of $(1 + x)^{44}$ are equal, then $x$ is equal to:

Question

If the 21^st and 22^nd terms in the expansion of $(1 + x)^{44}$ are equal, then $x$ is equal to:

$\frac{21}{22}$

$\frac{22}{23}$

$\frac{24}{21}$

$\frac{7}{8}$

Please login to view the detailed solution steps...