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Question

If \(f(x) = \begin{cases} \frac{3 \sin \pi x}{5x}, & x \neq 0, \\ 2K, & x = 0. \end{cases}\) is continuous at $ x = 0 $, then the value of $ K $ is

$\frac{3\pi}{10}$

$\frac{3\pi}{5}$

$\frac{\pi}{10}$

$\frac{3\pi}{2}$

Solution

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