Question
If $f(x) = f(\pi + e - x)$ and $\int_{e}^{\pi} f(x) \, dx = \frac{2}{e + \pi}$, then $\int_{e}^{\pi} x f(x) \, dx$ is equal to
If $f(x) = f(\pi + e - x)$ and $\int_{e}^{\pi} f(x) \, dx = \frac{2}{e + \pi}$, then $\int_{e}^{\pi} x f(x) \, dx$ is equal to