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Question

If $ \vec{a} = i + 2j + 2k $, $ |\vec{b}| = 5 $, and the angle between $ \vec{a} $ and $ \vec{b} $ is $ \frac{\pi}{6} $, then the area of the triangle formed by these two vectors as two sides is?

$\frac{15}{2}$

15

$\frac{15}{4}$

$\frac{15\sqrt{3}}{2}$

Solution

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