Equation of the line passing through the point (2, 3, 1) and parallel to the line of intersection of the planes $x - 2y - z + 5 = 0$ and $x + y + 3z = 6$ is:

Question

$\frac{x-2}{5} = \frac{y-3}{-4} = \frac{z-1}{3}$

$\frac{x-2}{-5} = \frac{y-3}{4} = \frac{z-1}{-3}$

$\frac{x-2}{5} = \frac{y-3}{4} = \frac{z-1}{-3}$

$\frac{x-2}{-5} = \frac{y-3}{-4} = \frac{z-1}{3}$

Solution

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