$ \int \frac{1}{x^2 (x^4 + 1)^{3/4}} \, dx $ is equal to _____________.
\(-\frac{(1 + x^4)^{\frac{1}{4}}}{x} + C \)
\(-\frac{(1 + x^4)^{\frac{1}{4}}}{x^2} + C \)
\(-\frac{(1 + x^4)^{\frac{1}{4}}}{2x} + C \)
\(-\frac{(1 + x^4)^{\frac{3}{4}}}{x} + C \)
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