A man takes a step forward with probability 0.4 and one step backward with probability 0.6. Then, the probability that at the end of eleven steps he is one step away from the starting point is?

Question

\({}^{11}C_5 \times (0.48)^5 \)

\({}^{11}C_6 \times (0.24)^5 \)

\({}^{11}C_5 \times (0.12)^5 \)

\({}^{11}C_6 \times (0.72)^5 \)

Solution

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