If $ y = \frac{1 - x^2}{1 + x^2} $, then $ \frac{dy}{dx} $ is equal to _______
$ \frac{-4x}{(1 + x^2)^2} $
$ \frac{-4x}{1 - x^4} $
$ \frac{1}{4 - x^4} $
$ \frac{-4x^3}{1 - x^4} $
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