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Question

If $ \sin x + \sin y = \frac{1}{2} $ and $ \cos x + \cos y = 1 $, then $ \tan (x+y) = \_ $

$\frac{8}{3}$

$-\frac{3}{4}$

$-\frac{8}{3}$

$\frac{4}{3}$

Solution

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