If $ \sin x + \sin y = \frac{1}{2} $ and $ \cos x + \cos y = 1 $, then $ \tan (x+y) = \_ $
$\frac{8}{3}$
$-\frac{3}{4}$
$-\frac{8}{3}$
$\frac{4}{3}$
Please login to view the detailed solution steps...
Subject Backlinks
Quiz Backlink
Related Question Backlinks