Let $f: \mathbb{R} \to \mathbb{R}$ be defined by $f(x) = 2x + 6$, which is a bijective mapping. Then $f^{-1}(x)$ is given by: - DASH

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Question

Let $f: \mathbb{R} \to \mathbb{R}$ be defined by $f(x) = 2x + 6$, which is a bijective mapping. Then $f^{-1}(x)$ is given by:

$\frac{x}{2} - 3$

$2x + 6$

$x - 3$

$6x + 2$

Solution

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