The value of $ \int e^{x^2(\tan^{-1}x + \tan^{-1}(x + 1))} \, \frac{dx}{x^2 + 1} $ is equal to

Question

$ e^{x \tan^{-1}x} + c $

$ \tan^{-1}(ex) + c $

$ \tan^{-1}(e^x) + c $

$ e^{\tan^{-1}x} + c $

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