The slope of the tangent to the curve $x = t^2 + 3t - 8$, $y = 2t^2 - 2t - 5$ at the point (2, -1) is
$\frac{22}{7}$
$\frac{6}{7}$
$\frac{7}{6}$
$-\frac{6}{7}$
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