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Question

The slope of the tangent to the curve $x = t^2 + 3t - 8$, $y = 2t^2 - 2t - 5$ at the point (2, -1) is

$\frac{22}{7}$

$\frac{6}{7}$

$\frac{7}{6}$

$-\frac{6}{7}$

Solution

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