The equation of the normal to the curve $y(1 + x^2) = 2 - x$ where the tangent crosses the x-axis is

Question

$(5x - y - 10 = 0)$

$(x - 5y - 10 = 0)$

$(5x + y + 10 = 0)$

$(x + 5y + 10 = 0)$

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