The eccentricity of the ellipse $\frac{x^2}{36} + \frac{y^2}{16} = 1$ is: - DASH

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Question

The eccentricity of the ellipse $\frac{x^2}{36} + \frac{y^2}{16} = 1$ is:

$\frac{2\sqrt{5}}{6}$

$\frac{2\sqrt{5}}{4}$

$\frac{2\sqrt{13}}{6}$

$\frac{2\sqrt{13}}{4}$

Solution

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