The range of $\sec^{-1} x$ is

Question

The range of $\sec^{-1} x$ is –

$\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$

$\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$

$\left[0, \pi\right]$

$\left[0, \pi\right] \setminus \left\{\frac{\pi}{2}\right\}$

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