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Question

If $f(x) = \begin{cases} x^2 & \text{if } x \leq 2 \\ \frac{k}{3} & \text{if } x > 2 \end{cases}$ is continuous at $x = 2$, then the value of $k$ is -

3

4

$\frac{3}{4}$

$\frac{4}{3}$

Solution

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