If $ y = \tan^{-1} \left( \frac{\sin x + \cos x}{\cos x - \sin x} \right) $, then $ \frac{dy}{dx} $ is equal to

Question

If $ y = \tan^{-1} \left( \frac{\sin x + \cos x}{\cos x - \sin x} \right) $, then $ \frac{dy}{dx} $ is equal to –

$\frac{1}{2}$

$\frac{\pi}{4}$

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