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Question

If $ y = \log(\log x) $ , then $ \frac{d^2y}{dx^2} $ is equal to –

$ -\frac{(1 + \log x)}{(x \log x)^2} $

$ -\frac{(1 + \log x)}{x^2 \log x} $

$ \frac{(1 + \log x)}{(x \log x)^2} $

$ \frac{(1 + \log x)}{x^2 \log x} $

Solution

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