$\int \frac{(x+3)e^x}{(x+4)^2} \, dx$ is equal to
$\frac{1}{(x+4)^2} + C$
$\frac{e^x}{(x+4)^2} + C$
$\frac{e^x}{(x+4)} + C$
$\frac{e^x}{(x+3)} + C$
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