The distance of the point (-2, 4, -5) from the line $\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6}$ is:

Question

$\frac{\sqrt{37}}{\sqrt{10}}$

$\frac{37}{10}$

$\frac{37}{\sqrt{10}}$

$\frac{37}{10}$

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