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Question

A box contains 100 pens, of which 10 are defective. The probability that, out of a sample of 5 pens drawn one by one with replacement, at most one is defective is –

$\frac{9}{10}$

$\frac{1}{2} \left(\frac{9}{10}\right)^4$

$\left(\frac{9}{10}\right)^5 + \frac{1}{2} \left(\frac{9}{10}\right)^4$

$\frac{1}{2} \left(\frac{9}{10}\right)^5 + \frac{1}{2} \left(\frac{9}{10}\right)^4$

Solution

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