If $(\left(\frac{1-i}{1+i}\right)^{96} = a + ib)$ then (a, b) is - DASH

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Question

If $(\left(\frac{1-i}{1+i}\right)^{96} = a + ib)$ then (a, b) is

(1, 1)

(1, 0)

(0, 1)

(0, -1)

Solution

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