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Question

If $f(x) = \begin{cases} \sqrt{1+kx} - \sqrt{1-kx} & \text{if } -1 \leq x \leq 0 \end{cases}$ is continuous at $x = 0$, then the value of $k$ is

$k = 1$

$k = -1$

$k = 0$

$k = 2$

Solution

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