Question
If $ f(x) = \begin{cases} \frac{\log x}{x - 1}, & x \neq 1 \\ k, & x = 1 \end{cases} $ is continuous at $ x = 1 $, then the value of $ k $ is:
If $ f(x) = \begin{cases} \frac{\log x}{x - 1}, & x \neq 1 \\ k, & x = 1 \end{cases} $ is continuous at $ x = 1 $, then the value of $ k $ is: