The function $f(x) = \sqrt{3} \sin 2x - \cos 2x + 4$ is one-to-one in the interval

Question

$\left[-\frac{\pi}{6}, \frac{\pi}{3}\right]$

$\left[\frac{\pi}{6}, \frac{2\pi}{3}\right]$

$\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$

$\left[-\frac{\pi}{6}, \frac{\pi}{3}\right]$

Please login to view the detailed solution steps...