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Question

If $A = \begin{bmatrix} 1 & 2 \\ 1 & 3 \end{bmatrix}$ and $B = \begin{bmatrix} 2 & 3 \\ 3 & 1 \\ 1 & 1 \end{bmatrix}$, then $AB'$ is equal to

$\begin{bmatrix} -3 & -2 \\ 10 & 7 \end{bmatrix}$

$\begin{bmatrix} -3 & 10 \\ 2 & 7 \end{bmatrix}$

$\begin{bmatrix} 7 & 10 \\ 2 & 3 \end{bmatrix}$

$\begin{bmatrix} -3 & 7 \\ 10 & -2 \end{bmatrix}$

Solution

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