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Question

If the parabola $y = \alpha x^2 - 6x + \beta$ passes through the point (0, 2) and has its tangent at $x = \frac{3}{2}$ parallel to the x-axis, then

$(\alpha = 2, \beta = -2)$

$(\alpha = -2, \beta = 2)$

$(\alpha = 2, \beta = 2)$

$(\alpha = -2, \beta = -2)$

Solution

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