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Question

The value of $\int \frac{x e^{x}}{(1 + x)^2} \, dx$ is equal to:

$e^{x}(1 + x) + c$

$e^{x}(1 + x)^2 + c$

$e^{x}(1 + x)^2 + c$

$\frac{e^{x}}{1 + x} + c$

Solution

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