If $ \vec{a} \cdot \vec{b} = 0 $ and $ \vec{a} + \vec{b} $ makes an angle of 60° with $ \vec{a} $, then
$ | \vec{a} | = 2 | \vec{b} | $
$ 2 | \vec{a} | = | \vec{b} | $
$ | \vec{a} | = \sqrt{3} | \vec{b} | $
$ \sqrt{3} | \vec{a} | = | \vec{b} | $
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