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Question

If a plane meets the coordinate axes at A, B, and C in such a way that the centroid of triangle ABC is at the point (1, 2, 3), then the equation of the plane is:

$\frac{x}{1} + \frac{y}{2} + \frac{z}{3} = 1$

$\frac{x}{3} + \frac{y}{6} + \frac{z}{9} = 1$

$\frac{x}{1} + \frac{y}{2} + \frac{z}{3} = \frac{1}{3}$

$\frac{x}{1} + \frac{y}{2} + \frac{z}{3} = -1$

Solution

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