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Question

The value of $\int \frac{1+x^4}{1+x^6} \, dx$ is

$\tan^{-1} x + \frac{1}{3} \tan^{-1} x^2 + C$

$\tan^{-1} x + \tan^{-1} x^3 + C$

$\tan^{-1} x + \frac{1}{3} \tan^{-1} x^3 + C$

$\tan^{-1} x - \frac{1}{3} \tan^{-1} x^3 + C$

Solution

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