Question
If \( |\vec{a} \times \vec{b}|^2 + (\vec{a} \cdot \vec{b})^2 = 144 \) and \( |\vec{a}| = 6 \), then \( |\vec{b}| \) is equal to:
If \( |\vec{a} \times \vec{b}|^2 + (\vec{a} \cdot \vec{b})^2 = 144 \) and \( |\vec{a}| = 6 \), then \( |\vec{b}| \) is equal to: