The sine of the angle between the straight line $\frac{x - 2}{3} = \frac{3 - y}{-4} = \frac{z - 4}{5}$ and the plane $2x - 2y + z = 5$ is:

Question

$\frac{\sqrt{2}}{10}$

$\frac{3}{\sqrt{50}}$

$\frac{4}{50}$

$\frac{5}{\sqrt{2}}$

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