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Question

If A and B are two events such that $P(A) = \frac{1}{3}$, $P(B) = \frac{1}{2}$, and $P(A \cap B) = \frac{1}{6}$, then $P(A' \mid B)$ is

$\frac{1}{12}$

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{1}{2}$

Solution

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