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Question

If $ f(x) = \sin^{-1}\left(\frac{2x}{1+x^2}\right) $, then $ f'(\sqrt{3}) $ is

$-\frac{1}{\sqrt{3}}$

$-\frac{1}{2}$

$\frac{1}{2}$

$\frac{1}{\sqrt{3}}$

Solution

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