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Question

If $\sum_{r=1}^{n} (2r-1) = x$ then $\lim_{n \to \infty} \left[ \frac{1^2}{x^2} + \frac{2^2}{x^2} + \frac{3^2}{x^2} + \ldots + \frac{n^2}{x^2} \right] =$

$\frac{1}{2}$

$\frac{1}{4}$

1

4

Solution

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