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Question

The right-hand and left-hand limits of the function $f(x) = \begin{cases} \frac{e^{1/x} - 1}{e^{1/x} + 1}, & \text{if } x \neq 0 \\ 0, & \text{if } x = 0 \end{cases}$ are respectively

-1 and 1

1 and 1

1 and -1

-1 and -1

Solution

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