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Question

In Young's double-slit experiment, the intensity of light passing through each of the two slits is $2 \times 10^{-2} \, \text{W/m}^{2}$. The screen-slit distance is very large compared to the slit-slit distance. The fringe width is $\beta$. The distance between the central maximum and a point $P$ on the screen is $x = \frac{\beta}{3}$. Then the total light intensity at that point is

$2 \times 10^{-2} \, \text{W/m}^{2}$

$16 \times 10^{-2} \, \text{W/m}^{2}$

$8 \times 10^{-2} \, \text{W/m}^{2}$

$4 \times 10^{-2} \, \text{W/m}^{2}$

Solution

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