Question
In the following equation representing $ \beta^{-} $ decay, the number of neutrons in the nucleus $ X $ is $ {}_{83}^{210}\text{Bi} \rightarrow X + e^{-} + \overline{\nu} $.
In the following equation representing $ \beta^{-} $ decay, the number of neutrons in the nucleus $ X $ is $ {}_{83}^{210}\text{Bi} \rightarrow X + e^{-} + \overline{\nu} $.