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Question

The electric field at a distance $r$ from an infinitely long, uniformly charged straight conductor with a linear charge density $\lambda$ is $E_1$. Another conductor, uniformly charged with the same linear charge density $\lambda$, is bent into a semicircle of radius $r$. The electric field at its center is $E_2$. Then,

$E_1 = E_2$

$E_1 = \pi r E_2$

$E_2 = \pi r E_1$

$E_2 = \frac{E_1}{r}$

Solution

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