A uniform electric field vector $ \vec{E} $ exists along the horizontal direction as shown. The electric potential at $ A $ is $ V_A $. A small point charge $ q $ is slowly taken from $ A $ to $ B $ along the curved path as shown. The potential energy of the charge when it is at point $ B $ is:

Question

$ q \left[ E x - V_A \right] $

$ q E x $

$ q \left[ V_{A} - E x \right] $

$ q \left[ V_{A} + E x \right] $

Solution

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