When $FeCl_3$ is added to excess hot water, it gives a sol $X$. When $FeCl_3$ is added to $NaOH$ (aq) solution, it gives a sol $Y$. $X$ and $Y$ formed in the above process, respectively, are:

Question

$Fe_2O_3 \cdot xH_2O / Cl^{-}$ and $Fe_2O_3 \cdot xH_2O / OH^{-}$

$Fe_2O_3 \cdot xH_2O / Fe^{3+}$ and $Fe_2O_3 \cdot xH_2O / OH^{-}$

$Fe_2O_3 \cdot xH_2O / OH^{-}$ and $Fe_2O_3 \cdot xH_2O / Fe^{3+}$

$Fe_2O_3 \cdot xH_2O / H^{+}$ and $Fe_2O_3 \cdot xH_2O / Na^{+}$

Solution

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